2021/Gareth solution Python/6.py

   1 #it is very not efficient for pt2 but I didn't have much time today to think of a better solution
   2 fish = [2,3,1,3,4,4,1,5,2,3,1,1,4,5,5,3,5,5,4,1,2,1,1,1,1,1,1,4,1,1,1,4,1,3,1,4,1,1,4,1,3,4,5,1,1,5,3,4,3,4,1,5,1,3,1,1,1,3,5,3,2,3,1,5,2,2,1,1,4,1,1,2,2,2,2,3,2,1,2,5,4,1,1,1,5,5,3,1,3,2,2,2,5,1,5,2,4,1,1,3,3,5,2,3,1,2,1,5,1,4,3,5,2,1,5,3,4,4,5,3,1,2,4,3,4,1,3,1,1,2,5,4,3,5,3,2,1,4,1,4,4,2,3,1,1,2,1,1,3,3,3,1,1,2,2,1,1,1,5,1,5,1,4,5,1,5,2,4,3,1,1,3,2,2,1,4,3,1,1,1,3,3,3,4,5,2,3,3,1,3,1,4,1,1,1,2,5,1,4,1,2,4,5,4,1,5,1,5,5,1,5,5,2,5,5,1,4,5,1,1,3,2,5,5,5,4,3,2,5,4,1,1,2,4,4,1,1,1,3,2,1,1,2,1,2,2,3,4,5,4,1,4,5,1,1,5,5,1,4,1,4,4,1,5,3,1,4,3,5,3,1,3,1,4,2,4,5,1,4,1,2,4,1,2,5,1,1,5,1,1,3,1,1,2,3,4,2,4,3,1]
   3 day = 0
   4 index = 0
   5 while True:
   6     if day == 256:
   7         break
   8     if index == len(fish):
   9         index = 0
  10         day = day + 1
  11         print("Day",day)
  12     if fish[index] == 0:
  13         fish[index] = 6
  14         fish.append(9)
  15     elif fish[index]!=0:
  16         fish[index]= fish[index]-1
  17     index = index + 1
  18 print("Number fo fish ",len(fish))